H2SO4 + K2Cr2O7 + 4 H2O2 → 5 H2O + K2SO4 + 2 CrO5
This is an oxidation-reduction (redox) reaction:
8 O-I + 8 e- → 8 O-II (reduction)
2 CrVI - 8 e- → 2 CrX (oxidation)
H2O2 is an oxidizing agent, K2Cr2O7 is a reducing agent.
This is an oxidation-reduction (redox) reaction:
8 O-I + 8 e- → 8 O-II (reduction)
2 CrVI - 8 e- → 2 CrX (oxidation)
H2O2 is an oxidizing agent, K2Cr2O7 is a reducing agent.
Reactants:
Products: