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Cu
+
H
3
P
O
4
→
Ø
This reaction
does not occur
under the normal conditions, because
H
2
is more reactive than
Cu
. The reaction should go in the reverse:
3
Cu
+
2
H
3
P
O
4
←
3
H
2
+
Cu
3
(
P
O
4
)
2