2 Pb + 2 NaOH + 6 H2O → 2 Na[Pb(OH)4] + 3 H2
This is a complexation reaction: Na[Pb(OH)4] is the formed complex.
This is an oxidation-reduction (redox) reaction:
2 Pb0 - 6 e- → 2 PbIII (oxidation)
6 HI + 6 e- → 6 H0 (reduction)
Warning: Unknown compound 'Na[Pb(OH)4]'