10 NaOH (aq) + 3 H2O2 (aq) + 2 Cr(NO3)3 (aq) → 8 H2O (l) + 6 NaNO3 (aq) + 2 Na2CrO4 (aq)
This is an oxidation-reduction (redox) reaction:
6 O-I + 6 e- → 6 O-II (reduction)
2 CrIII - 6 e- → 2 CrVI (oxidation)
H2O2 is an oxidizing agent, Cr(NO3)3 is a reducing agent.