6 NaI + 2 K2CrO4 + 8 H2O → 2 Cr(OH)3 + 3 I2 + 6 NaOH + 4 KOH
This is an oxidation-reduction (redox) reaction:
6 I-I - 6 e- → 6 I0 (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
NaI is a reducing agent, K2CrO4 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
6 I-I - 6 e- → 6 I0 (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
NaI is a reducing agent, K2CrO4 is an oxidizing agent.
Reactants:
Products: