8 NaHRhO4 + 2 H[BF4] → 6 NaRhO4 + Rh2O3 + 5 H2O + 2 Na[BF4]
This is an oxidation-reduction (redox) reaction:
6 RhVI - 6 e- → 6 RhVII (oxidation)
2 RhVI + 6 e- → 2 RhIII (reduction)
NaHRhO4 is both an oxidizing and a reducing agent (disproportionation (dismutation)).
Reactants:
- NaHRhO4
- H[BF4]
Products: