Na2Cr2O7 + 3 H2O2 + 4 H2SO4 → Na2SO4 + Cr2(SO4)3 + 3 O2 + 7 H2O
This is an oxidation-reduction (redox) reaction:
2 CrVI + 6 e- → 2 CrIII (reduction)
6 O-I - 6 e- → 6 O0 (oxidation)
Na2Cr2O7 is an oxidizing agent, H2O2 is a reducing agent.
This is an oxidation-reduction (redox) reaction:
2 CrVI + 6 e- → 2 CrIII (reduction)
6 O-I - 6 e- → 6 O0 (oxidation)
Na2Cr2O7 is an oxidizing agent, H2O2 is a reducing agent.
Reactants:
Products: