2 (Mn)2+ + 5 Na2O2 + 4 H+ → 2 (MnO4)- + 10 Na+ + 2 H2O
This is an oxidation-reduction (redox) reaction:
2 MnII - 10 e- → 2 MnVII (oxidation)
10 O-I + 10 e- → 10 O-II (reduction)
Mn2+ is a reducing agent, Na2O2 is an oxidizing agent.
Reactants:
- Mn2+
- Na2O2
- H+
Products: