16 Li + S8 → 8 Li2S
This is an oxidation-reduction (redox) reaction:
8 S0 + 16 e- → 8 S-II (reduction)
16 Li0 - 16 e- → 16 LiI (oxidation)
S8 is an oxidizing agent, Li is a reducing agent.
This is an oxidation-reduction (redox) reaction:
8 S0 + 16 e- → 8 S-II (reduction)
16 Li0 - 16 e- → 16 LiI (oxidation)
S8 is an oxidizing agent, Li is a reducing agent.
Reactants:
Products: