4 Li + O2 → 2 Li2O
This is an oxidation-reduction (redox) reaction:
4 Li0 - 4 e- → 4 LiI (oxidation)
2 O0 + 4 e- → 2 O-II (reduction)
Li is a reducing agent, O2 is an oxidizing agent.
Reactants:
- Li
- O2
Products:
This is an oxidation-reduction (redox) reaction:
4 Li0 - 4 e- → 4 LiI (oxidation)
2 O0 + 4 e- → 2 O-II (reduction)
Li is a reducing agent, O2 is an oxidizing agent.
Reactants:
Products: