Li + H2 → LiH2
This is an oxidation-reduction (redox) reaction:
2 H0 + e- → 2 H-1/2 (reduction)
Li0 - 1 e- → LiI (oxidation)
H2 is an oxidizing agent, Li is a reducing agent.
This is an oxidation-reduction (redox) reaction:
2 H0 + e- → 2 H-1/2 (reduction)
Li0 - 1 e- → LiI (oxidation)
H2 is an oxidizing agent, Li is a reducing agent.
Reactants:
Products: