6 KOH (aq) + KClO3 (aq) + 3 MnCl2 (aq) → 3 H2O (l) + 7 KCl (aq) + 3 MnO2 (s)
This is an oxidation-reduction (redox) reaction:
3 MnII - 6 e- → 3 MnIV (oxidation)
ClV + 6 e- → Cl-I (reduction)
MnCl2 is a reducing agent, KClO3 is an oxidizing agent.
This is a precipitation reaction: MnO2 is the formed precipitate.