8 KOH + 3 Br2 + 2 Cr(OH)3 → 7 H2O + K2Cr2O7 + 6 KBr
This is an acid-base reaction (neutralization): KOH is a base, Cr(OH)3 is an acid.
This is an oxidation-reduction (redox) reaction:
6 Br0 + 6 e- → 6 Br-I (reduction)
2 CrIII - 6 e- → 2 CrVI (oxidation)
Br2 is an oxidizing agent, Cr(OH)3 is a reducing agent.