2 KCr2O7 + 7 NaNO2 + 7 H2SO4 → 7 NaNO3 + 2 Cr2(SO4)3 + K2SO4 + 7 H2O
This is an oxidation-reduction (redox) reaction:
7 NIII - 14 e- → 7 NV (oxidation)
4 Cr13/2 + 14 e- → 4 CrIII (reduction)
NaNO2 is a reducing agent, KCr2O7 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
7 NIII - 14 e- → 7 NV (oxidation)
4 Cr13/2 + 14 e- → 4 CrIII (reduction)
NaNO2 is a reducing agent, KCr2O7 is an oxidizing agent.
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