6 HCl + 4 NaI + Na2TeO3 → 3 H2O + 6 NaCl + 2 I2 + Te
This is an oxidation-reduction (redox) reaction:
TeIV + 4 e- → Te0 (reduction)
4 I-I - 4 e- → 4 I0 (oxidation)
Na2TeO3 is an oxidizing agent, NaI is a reducing agent.
Reactants:
- HCl – Chlorane , Hydrogen chloride
- Other names: Hydrochloric acid , M , Uriatic acid
- Appearance: Colorless, transparent liquid, fumes in air if concentrated ; Colorless gas ; Colourless compressed liquefied gas with pungent odour ; Colorless to slightly yellow gas with a pungent, irritating odor. [Note: Shipped as a liquefied compressed gas.]
- NaI
- Na2TeO3
Products: