CrCl2 (aq) + 8 KOH (aq) + 2 Br2 (aq) → 4 KBr (aq) + 2 KCl (aq) + K2CrO4 (aq) + 4 H2O (l)
This is an oxidation-reduction (redox) reaction:
4 Br0 + 4 e- → 4 Br-I (reduction)
CrII - 4 e- → CrVI (oxidation)
Br2 is an oxidizing agent, CrCl2 is a reducing agent.