Cr2O7 + 7 SO3 → 2 Cr + 7 SO4
This is an oxidation-reduction (redox) reaction:
7 SVI - 14 e- → 7 SVIII (oxidation)
2 CrVII + 14 e- → 2 Cr0 (reduction)
SO3 is a reducing agent, Cr2O7 is an oxidizing agent.
Warning: Unknown compound 'Cr2O7'
Warning: Unknown compound 'SO4'