2 (Cr)3+ + 5 H2O2 + 6 OH- → 2 CrO4 + 8 H2O
This is an oxidation-reduction (redox) reaction:
2 CrIII - 10 e- → 2 CrVIII (oxidation)
10 O-I + 10 e- → 10 O-II (reduction)
Cr3+ is a reducing agent, H2O2 is an oxidizing agent.
Warning: Unknown compound 'CrO4'