8 (Br)- + Cr2O7 + 14 H+ → 4 Br2 + 2 (Cr)3+ + 7 H2O
This is an oxidation-reduction (redox) reaction:
8 Br-I - 8 e- → 8 Br0 (oxidation)
2 CrVII + 8 e- → 2 CrIII (reduction)
Br- is a reducing agent, Cr2O7 is an oxidizing agent.
Warning: Unknown compound 'Cr2O7'