5 Ba(IO3)2 → 9 O2 + 4 I2 + Ba5(IO6)2
This is an oxidation-reduction (redox) reaction:
8 IV + 40 e- → 8 I0 (reduction)
2 IV - 4 e- → 2 IVII (oxidation)
18 O-II - 36 e- → 18 O0 (oxidation)
Ba(IO3)2 is an oxidizing agent, Ba(IO3)2 is a reducing agent, Ba(IO3)2 is a reducing agent.
Reactants:
Products: