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Au
+
H
2
S
O
4
→
Ø
This reaction
does not occur
under the normal conditions, because
H
2
is more reactive than
Au
. The reaction should go in the reverse:
2
Au
+
3
H
2
S
O
4
←
Au
2
(
S
O
4
)
3
+
3
H
2