2 Na2S2O3 + I2 → Na2S4O6 + 2 NaI
This is an oxidation-reduction (redox) reaction:
4 SII - 2 e- → 4 S5/2 (oxidation)
2 I0 + 2 e- → 2 I-I (reduction)
Na2S2O3 is a reducing agent, I2 is an oxidizing agent.
Reactants:
- Na2S2O3
- I2
Products:
This is an oxidation-reduction (redox) reaction:
4 SII - 2 e- → 4 S5/2 (oxidation)
2 I0 + 2 e- → 2 I-I (reduction)
Na2S2O3 is a reducing agent, I2 is an oxidizing agent.
Reactants:
Products: