2 MnCl2 (aq) + 5 KClO (l) + 6 KOH (aq) → 2 KMnO4 (aq) + 9 KCl (aq) + 3 H2O (l)
This is an oxidation-reduction (redox) reaction:
2 MnII - 10 e- → 2 MnVII (oxidation)
5 ClI + 10 e- → 5 Cl-I (reduction)
MnCl2 is a reducing agent, KClO is an oxidizing agent.