MnCl2 (aq) + Br2 (aq) + 4 NaOH (aq) → MnO2 (s) + 2 NaBr (aq) + 2 NaCl (aq) + 2 H2O (l)
This is an oxidation-reduction (redox) reaction:
2 Br0 + 2 e- → 2 Br-I (reduction)
MnII - 2 e- → MnIV (oxidation)
Br2 is an oxidizing agent, MnCl2 is a reducing agent.
This is a precipitation reaction: MnO2 is the formed precipitate.