2 Mn(OH)2 + 5 Br2 + 12 KOH → 8 H2O + 2 KMnO4 + 10 KBr
This is an oxidation-reduction (redox) reaction:
10 Br0 + 10 e- → 10 Br-I (reduction)
2 MnII - 10 e- → 2 MnVII (oxidation)
Br2 is an oxidizing agent, Mn(OH)2 is a reducing agent.
This is an oxidation-reduction (redox) reaction:
10 Br0 + 10 e- → 10 Br-I (reduction)
2 MnII - 10 e- → 2 MnVII (oxidation)
Br2 is an oxidizing agent, Mn(OH)2 is a reducing agent.
Reactants:
Products: