4 H2SO4 + K2CrO7 + 3 H2O2 → Cr(SO4)3 + K2SO4 + 7 H2O + 3 O2
This is an oxidation-reduction (redox) reaction:
6 O-I - 6 e- → 6 O0 (oxidation)
CrXII + 6 e- → CrVI (reduction)
H2O2 is a reducing agent, K2CrO7 is an oxidizing agent.
Warning: Unknown compound 'K2CrO7'