7 H2SO4 + K2Cr2O7 + 3 SnSO4 → 7 H2O + K2SO4 + Cr2(SO4)3 + 3 Sn(SO4)2
This is an oxidation-reduction (redox) reaction:
3 SnII - 6 e- → 3 SnIV (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
SnSO4 is a reducing agent, K2Cr2O7 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
3 SnII - 6 e- → 3 SnIV (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
SnSO4 is a reducing agent, K2Cr2O7 is an oxidizing agent.
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