CrCl3 + 4 NaOH + 2 H2O2 → NaCrO4 + 3 NaCl + 4 H2O
This is an oxidation-reduction (redox) reaction:
CrIII - 4 e- → CrVII (oxidation)
4 O-I + 4 e- → 4 O-II (reduction)
CrCl3 is a reducing agent, H2O2 is an oxidizing agent.
Warning: Unknown compound 'NaCrO4'