Cr2O3 + 10 KOH + 6 NO2 → 6 KNO2 + 2 K2CrO4 + 5 H2O
This is an acid-base reaction (neutralization): KOH is a base, NO2 is an acid.
This is an oxidation-reduction (redox) reaction:
6 NIV + 6 e- → 6 NIII (reduction)
2 CrIII - 6 e- → 2 CrVI (oxidation)
NO2 is an oxidizing agent, Cr2O3 is a reducing agent.
- KOH – Potassium hydroxide
- NO2 – Nitrogen dioxide
- Other names: Nitrogen(IV) oxide , Deutoxide of nitrogen , Nitrogen peroxide
- Appearance: Brown gas ; Reddish-brown gas or brown or yellow liquid with pungent odour ; Yellowish-brown liquid or reddish-brown gas (above 70°F) with a pungent, acrid odor. [Note: In solid form (below 15°F) it is found structurally as N2O4.]
- K2CrO4 – Potassium chromate
- H2O – Water, oxidane