2 BiCl3 + 10 KMnO4 + 12 KOH → 3 Cl2 + 2 KBiO3 + 10 K2MnO4 + 6 H2O
This is an oxidation-reduction (redox) reaction:
10 MnVII + 10 e- → 10 MnVI (reduction)
2 BiIII - 4 e- → 2 BiV (oxidation)
6 Cl-I - 6 e- → 6 Cl0 (oxidation)
KMnO4 is an oxidizing agent, BiCl3 is a reducing agent, BiCl3 is a reducing agent.