3 NaBH4 + SbCl3 → 3 BH3 + SbH3 + 3 NaCl
This is an oxidation-reduction (redox) reaction:
3 B-V - 6 e- → 3 B-III (oxidation)
SbIII + 6 e- → Sb-III (reduction)
NaBH4 is a reducing agent, SbCl3 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
3 B-V - 6 e- → 3 B-III (oxidation)
SbIII + 6 e- → Sb-III (reduction)
NaBH4 is a reducing agent, SbCl3 is an oxidizing agent.