64 Na(OH) + 2 CrCl3 + 27 I2 → 6 NaClO4 + 54 NaI + 2 Na2CrO4 + 32 H2O
This is an oxidation-reduction (redox) reaction:
6 Cl-I - 48 e- → 6 ClVII (oxidation)
54 I0 + 54 e- → 54 I-I (reduction)
2 CrIII - 6 e- → 2 CrVI (oxidation)
CrCl3 is a reducing agent, I2 is an oxidizing agent, CrCl3 is a reducing agent.