8 KMnO4 (aq) + 3 KCl (aq) + 4 H2O (l) → 3 KClO4 (s) + 8 MnO2 (s) + 8 KOH (aq)
This is an oxidation-reduction (redox) reaction:
8 MnVII + 24 e- → 8 MnIV (reduction)
3 Cl-I - 24 e- → 3 ClVII (oxidation)
KMnO4 is an oxidizing agent, KCl is a reducing agent.