14 HBr + K2Cr2O7 → 2 CrBr + 2 KBr + 7 H2O + 5 Br2
This is an oxidation-reduction (redox) reaction:
10 Br-I - 10 e- → 10 Br0 (oxidation)
2 CrVI + 10 e- → 2 CrI (reduction)
HBr is a reducing agent, K2Cr2O7 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
10 Br-I - 10 e- → 10 Br0 (oxidation)
2 CrVI + 10 e- → 2 CrI (reduction)
HBr is a reducing agent, K2Cr2O7 is an oxidizing agent.
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