H₂Se^IVO₃ + 2 Zn⁰ + 4 HCl → 2 Zn^IICl₂ + Se⁰ + 3 H₂O

This is an oxidation-reduction (redox) reaction:

Se^IV + 4 e^- → Se⁰ (reduction)

2 Zn⁰ - 4 e^- → 2 Zn^II (oxidation)

Change the oxidation states

Search by reactants (H₂SeO₃, Zn, HCl)

1.	H2SeO3 + Zn + HCl → ZnCl2 + Se + H2O

Search by products (ZnCl₂, Se, H₂O)

1.	H2SeO3 + Zn + HCl → ZnCl2 + Se + H2O

Search by reactants (H₂SeO₃, Zn, HCl) and by products (ZnCl₂, Se, H₂O)

1.	H2SeO3 + Zn + HCl → ZnCl2 + Se + H2O