3 H2O2 + 2 NaOH + 2 KMnO4 → K2MnO2 + Na2MnO4 + 3 O2 + 4 H2O
This is an oxidation-reduction (redox) reaction:
MnVII + 5 e- → MnII (reduction)
MnVII + e- → MnVI (reduction)
6 O-I - 6 e- → 6 O0 (oxidation)
KMnO4 is an oxidizing agent, KMnO4 is an oxidizing agent, H2O2 is a reducing agent.