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Error: Error in balancing the equation: There is an infinite amount of solutions.
?
Fe
_{2}
(
S
O
_{4}
)
_{3}
+
?
H
_{2}
O
→
?
Fe
(
O
H
)
_{3}
+
?
Fe
+
?
H
_{2}
+
?
H
_{2}
S
O
_{4}
+
?
O
_{2}
Search by reactants (
Fe
_{2}
(
S
O
_{4}
)
_{3}
,
H
_{2}
O
)
1
2
1.
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→ Fe(OH)
_{3}
+ H
_{2}
SO
_{4}
2.
SO
_{2}
+
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→ FeSO
_{4}
+ H
_{2}
SO
_{4}
3.
Fe
_{2}
(SO
_{4}
)
_{3}
+ NH
_{3}
+
H
_{2}
O
→ Fe(OH)
_{3}
+ (NH
_{4}
)
_{2}
SO
_{4}
4.
Na
_{2}
SO
_{3}
+
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→ Na
_{2}
SO
_{4}
+ FeSO
_{4}
+ H
_{2}
SO
_{4}
5.
CuFeS
_{2}
+
Fe
_{2}
(SO
_{4}
)
_{3}
+ O
_{2}
+
H
_{2}
O
→ CuSO
_{4}
+ FeSO
_{4}
+ H
_{2}
SO
_{4}
6.
Cr
_{2}
(SO
_{4}
)
_{3}
+
Fe
_{2}
(SO
_{4}
)
_{3}
+ K
_{2}
SO
_{4}
+
H
_{2}
O
→ K
_{2}
Cr
_{2}
O
_{7}
+ FeSO
_{4}
+ H
_{2}
SO
_{4}
7.
Na
_{2}
CO
_{3}
+
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→ Fe(OH)
_{3}
+ Na
_{2}
SO
_{4}
+ H
_{2}
SO
_{4}
+ CO
_{2}
8.
Na
_{2}
SO
_{3}
+
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→ Fe(OH)
_{3}
+ SO
_{2}
+ Na
_{2}
SO
_{4}
9.
MnO
_{2}
+
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→ HMnO
_{4}
+ FeSO
_{4}
+ H
_{2}
SO
_{4}
10.
KCl +
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→ KClO
_{3}
+ FeSO
_{4}
+ H
_{2}
SO
_{4}
1
2
Search by products (
Fe
(
O
H
)
_{3}
,
Fe
,
H
_{2}
,
H
_{2}
S
O
_{4}
,
O
_{2}
)
1.
Fe
_{2}
(SO
_{4}
)
_{3}
+ H
_{2}
O →
Fe(OH)
_{3}
+
Fe
+
H
_{2}
+
H
_{2}
SO
_{4}
+
O
_{2}
Search by reactants (
Fe
_{2}
(
S
O
_{4}
)
_{3}
,
H
_{2}
O
) and by products (
Fe
(
O
H
)
_{3}
,
Fe
,
H
_{2}
,
H
_{2}
S
O
_{4}
,
O
_{2}
)
1.
Fe
_{2}
(SO
_{4}
)
_{3}
+
H
_{2}
O
→
Fe(OH)
_{3}
+
Fe
+
H
_{2}
+
H
_{2}
SO
_{4}
+
O
_{2}