3 C2H5OH + Cr2O72- + 8 H+ → 3 C2H4O + 2 (Cr)3+ + 7 H2O
This is an oxidation-reduction (redox) reaction:
6 C-II - 6 e- → 6 C-I (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
C2H5OH is a reducing agent, Cr2O72- is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
6 C-II - 6 e- → 6 C-I (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
C2H5OH is a reducing agent, Cr2O72- is an oxidizing agent.
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