3 (NH4)2S + K2Cr2O7 + 7 H2O → 6 NH4OH + 2 Cr(OH)3 + 3 S + 2 KOH
This is an oxidation-reduction (redox) reaction:
3 S-II - 6 e- → 3 S0 (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
(NH4)2S is a reducing agent, K2Cr2O7 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
3 S-II - 6 e- → 3 S0 (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
(NH4)2S is a reducing agent, K2Cr2O7 is an oxidizing agent.
Reactants:
Products: