14 Li + 8 H2O + 2 LiClO4 → 16 LiOH + Cl2
This is an oxidation-reduction (redox) reaction:
2 ClVII + 14 e- → 2 Cl0 (reduction)
14 Li0 - 14 e- → 14 LiI (oxidation)
LiClO4 is an oxidizing agent, Li is a reducing agent.
This is an oxidation-reduction (redox) reaction:
2 ClVII + 14 e- → 2 Cl0 (reduction)
14 Li0 - 14 e- → 14 LiI (oxidation)
LiClO4 is an oxidizing agent, Li is a reducing agent.
Reactants:
Products: