2 KCr2O7 + 28 HBr → 4 CrBr + 11 Br2 + 2 KBr + 14 H2O
This is an oxidation-reduction (redox) reaction:
22 Br-I - 22 e- → 22 Br0 (oxidation)
4 Cr13/2 + 22 e- → 4 CrI (reduction)
HBr is a reducing agent, KCr2O7 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
22 Br-I - 22 e- → 22 Br0 (oxidation)
4 Cr13/2 + 22 e- → 4 CrI (reduction)
HBr is a reducing agent, KCr2O7 is an oxidizing agent.
Reactants:
Products: