2 K(Cr(OH)4) + 3 H2O2 + 2 KOH → 2 K2CrO4 + 8 H2O
This is an oxidation-reduction (redox) reaction:
2 CrIII - 6 e- → 2 CrVI (oxidation)
6 O-I + 6 e- → 6 O-II (reduction)
K(Cr(OH)4) is a reducing agent, H2O2 is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
2 CrIII - 6 e- → 2 CrVI (oxidation)
6 O-I + 6 e- → 6 O-II (reduction)
K(Cr(OH)4) is a reducing agent, H2O2 is an oxidizing agent.
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