2 Na2S2O3 + 2 I2 → 2 NaI2 + Na2S4O6
This is an oxidation-reduction (redox) reaction:
2 NaI - 2 e- → 2 NaII (oxidation)
4 SII - 2 e- → 4 S5/2 (oxidation)
4 I0 + 4 e- → 4 I-I (reduction)
Na2S2O3 is a reducing agent, Na2S2O3 is a reducing agent, I2 is an oxidizing agent.
Reactants:
- Na2S2O3
- I2
Products: