Na2MnO4 + 4 NaI + 4 H2SO4 → 3 Na2SO4 + 2 I2 + MnSO4 + 4 H2O
This is an oxidation-reduction (redox) reaction:
MnVI + 4 e- → MnII (reduction)
4 I-I - 4 e- → 4 I0 (oxidation)
Na2MnO4 is an oxidizing agent, NaI is a reducing agent.
This is an oxidation-reduction (redox) reaction:
MnVI + 4 e- → MnII (reduction)
4 I-I - 4 e- → 4 I0 (oxidation)
Na2MnO4 is an oxidizing agent, NaI is a reducing agent.
Reactants:
Products: