2 KCr2O7 + 14 KBr + 14 H2SO4 → 2 Cr2(SO4)3 + 8 K2SO4 + 14 H2O + 7 Br2
This is an oxidation-reduction (redox) reaction:
14 Br-I - 14 e- → 14 Br0 (oxidation)
4 Cr13/2 + 14 e- → 4 CrIII (reduction)
KBr is a reducing agent, KCr2O7 is an oxidizing agent.