18 KBr + 2 K2CrO7 + 14 H2SO4 → 9 Br2 + Cr2(SO4)3 + 11 K2SO4 + 14 H2O
This is an oxidation-reduction (redox) reaction:
18 Br-I - 18 e- → 18 Br0 (oxidation)
2 CrXII + 18 e- → 2 CrIII (reduction)
KBr is a reducing agent, K2CrO7 is an oxidizing agent.
Warning: Unknown compound 'K2CrO7'