2 K(Cr(OH)4) + 3 Br2 + 2 KOH → 2 K2CrO4 + 6 HBr + 2 H2O
This is an oxidation-reduction (redox) reaction:
6 Br0 + 6 e- → 6 Br-I (reduction)
2 CrIII - 6 e- → 2 CrVI (oxidation)
Br2 is an oxidizing agent, K(Cr(OH)4) is a reducing agent.
This is an oxidation-reduction (redox) reaction:
6 Br0 + 6 e- → 6 Br-I (reduction)
2 CrIII - 6 e- → 2 CrVI (oxidation)
Br2 is an oxidizing agent, K(Cr(OH)4) is a reducing agent.
Reactants:
Products: