2 Cr(OH)3 + 10 KOH + 3 Br2 → 6 KBr + 2 K2CrO4 + 8 H2O
This is an acid-base reaction (neutralization): Cr(OH)3 is an acid, KOH is a base.
This is an oxidation-reduction (redox) reaction:
6 Br0 + 6 e- → 6 Br-I (reduction)
2 CrIII - 6 e- → 2 CrVI (oxidation)
Br2 is an oxidizing agent, Cr(OH)3 is a reducing agent.