C2H5OH + 2 Cr2O72- + 16 H+ → 4 (Cr)3+ + 2 CO2 + 11 H2O
This is an oxidation-reduction (redox) reaction:
2 C-II - 12 e- → 2 CIV (oxidation)
4 CrVI + 12 e- → 4 CrIII (reduction)
C2H5OH is a reducing agent, Cr2O72- is an oxidizing agent.
This is an oxidation-reduction (redox) reaction:
2 C-II - 12 e- → 2 CIV (oxidation)
4 CrVI + 12 e- → 4 CrIII (reduction)
C2H5OH is a reducing agent, Cr2O72- is an oxidizing agent.
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