6 Ba(OH)2 + 7 I2 → 4 BaI2 + 2 Ba(IO)3 + 6 H2O
This is an oxidation-reduction (redox) reaction:
6 I0 - 8 e- → 6 I4/3 (oxidation)
8 I0 + 8 e- → 8 I-I (reduction)
I2 is both an oxidizing and a reducing agent (disproportionation (dismutation)).
This is an oxidation-reduction (redox) reaction:
6 I0 - 8 e- → 6 I4/3 (oxidation)
8 I0 + 8 e- → 8 I-I (reduction)
I2 is both an oxidizing and a reducing agent (disproportionation (dismutation)).
Reactants:
Products: